Chi Square Test Example Problems With Answers. Applying the chi square test for independence to sample data we compute the degrees of freedom the expected frequency counts and the chi square test statistic. For yellow we have 46 100 2 100 29 16.
A chi square goodness of fit test revealed that the sample proportions collected did differ significantly from that of the population x2 5 n 90 15 38 p 05. Continue doing this for the rest of the cells and add the final numbers for each cell together to get the final chi square number. Chi n 1 2 frac left n 1 right s 2 sigma 0 2 where.
A chi square statistic with n 1 degrees of freedom is computed as.
Applying the chi square test for independence to sample data we compute the degrees of freedom the expected frequency counts and the chi square test statistic. Therefore 6 6 24 2 6 24 0 0092. For yellow we have 46 100 2 100 29 16. Chi square test of independence example likewise we can use the chi square test for homogeneity of proportions to see if different populations have the same proportion of individuals with similar characteristics.
